Question
1. y' + 2sin2πx = 0 2. y' + xe-x2/2 = 0 3. y' = y
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Question
1. y' + 2sin2πx = 0 2. y' + xe-x2/2 = 0 3. y' = y
STEP by STEP SOLUTION On YouTube Video
Subscribe our channel for more videos
FaceBook:
www.facebook.com/MuhammadaAli5110
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